使用SQL从公式（字符串）中提取整数

Question

I have a column with formulas. I need to extract only the integers present in the formula and put them in the next row. For this formula,

Column A
(((23-22)/23)*100)

The output expected is as below without 100

   Column A
   23
   22 

I want to implement this in sql. Please help. Thanks in advance.

Edit1: The integers in the formula are actually the ids from another table. I need to join the tables on the IDs present in this formula

Table 1          Table 2
Tbl1ID           Tabl2Id    Formula
22               1          (((23-22)/23)*100)
23               2          24 + 25
24               
25

I have seen to it that Table 1 does not have Tbl1ID as 100.

Edit2: Probably my approach is not right. The actual requirement is I need to replace the integers with a name associated to the id.

Table 1            Table 2                          Table 3(Required)
Tbl1ID    Name     Tbl2Id    Formula                Col1
  23      a         1       (((23-22)/23)*100)      (((a-b)/a)*100)
  22      b               

Answer 1

Try this:

DECLARE @TEST TABLE (TBL1ID INT)
INSERT INTO @TEST VALUES ('22')
INSERT INTO @TEST VALUES ('23')
INSERT INTO @TEST VALUES ('24')
INSERT INTO @TEST VALUES ('25')

DECLARE @NUM TABLE (INTE INT)
DECLARE @FORM VARCHAR(100)='(((23-22)/23)*100)',@VAL VARCHAR(MAX)

WHILE( PATINDEX('%[0-9]%',@FORM))>0
BEGIN
    SET @VAL=(SELECT LEFT(VAL,PATINDEX('%[^0-9]%', VAL+'A')-1) FROM(
        SELECT SUBSTRING(@FORM, PATINDEX('%[0-9]%', @FORM), LEN(@FORM)) VAL )X)
    INSERT INTO @NUM VALUES( @VAL)
    SET @FORM= SUBSTRING(@FORM, PATINDEX('%[0-9]%', @FORM)+LEN(@VAL),LEN(@FORM))
END

SELECT DISTINCT * FROM @NUM WHERE INTE IN (SELECT * FROM @TEST)