如何从PHP发送XML

Question

I'm trying to send XML in my code but it also includes unwanted stuff. 我正在尝试在代码中发送XML，但其中还包含不需要的内容。 Here is my code: 这是我的代码：

<!DOCTYPE html>
<html>
<body>
    <?php
        class InfoDB extends SQLite3{
            function __construct(){
               $this->open('info.db');
            }
        }           
        $db = new InfoDB();
        $result = $db->query('SELECT * FROM members WHERE age=' . $q . '');

        $xml = new DOMDocument();
        $xml_info = $xml->createElement("Info");
        $result = $db->query('SELECT * FROM members');
        while($row = $result->fetchArray()) {
            $xml_member = $xml->createElement("Member");
            $name_attribute = $xml->createAttribute('Name');
            $name_attribute->value = $row['name'];
            $xml_member->appendChild($name_attribute);
            $age_attribute = $xml->createAttribute('Age');
            $age_attribute->value = $row['age'];
            $xml_member->appendChild($age_attribute);
            $xml_info->appendChild($xml_member);
        }
        $xml->appendChild( $xml_info );
        $xml->save("members.xml"); 
        $db->close();
        print $xml->saveXML();
        //// I tried the following lines with no luck
        // $file = file_get_contents('club-members.xml');
        // echo htmlspecialchars($file, ENT_QUOTES);

        //// The following line means no output at all!!!
        // header('Content-type: text/xml');
    ?>
</body>
</html>

So what I get is like: 所以我得到的像是：

<!DOCTYPE html>
<html>
  <body>
   <?xml version="1.0"?>
   <Info>
     <Member Name="Person A" Age="23"/>
     <Member Name="Person B" Age="33"/>
     <Member Name="Person C" Age="43"/>
   </Info>
  </body>
</html>

But what I need is only the XML bits, like: 但是我只需要XML位，例如：

<?xml version="1.0"?>
<Info>
  <Member Name="Person A" Age="23"/>
  <Member Name="Person B" Age="33"/>
  <Member Name="Person C" Age="43"/>
</Info>

If I use the following line of code 如果我使用以下代码

header('Content-type: text/xml');

I get this error: 我收到此错误：

This page contains the following errors: error on line 4 at column 14: 此页面包含以下错误：第4行第14列的错误：

XML declaration allowed only at the start of the document 仅在文档开始处允许XML声明

Below is a rendering of the page up to the first error. 下面是直到第一个错误的页面呈现。

What am I missing? 我想念什么？ Thanks for the help. 谢谢您的帮助。

Answer 1

Multiple issues: 多个问题：

You cannot change headers after output has started. 开始输出后，您将无法更改标题。 Put your header function at the start of your PHP script. 将header函数放在PHP脚本的开头。
You've declared the document as an HTML document and include various HTML elements, but you want an XML document. 您已将文档声明为HTML文档，并包含各种HTML元素，但是您需要XML文档。

Use the following: 使用以下内容：

<?php
    header('Content-type: text/xml');

    class InfoDB extends SQLite3{
        function __construct(){
           $this->open('info.db');
        }
    }           
    $db = new InfoDB();
    $result = $db->query('SELECT * FROM members WHERE age=' . $q . '');

    $xml = new DOMDocument();
    $xml_info = $xml->createElement("Info");
    $result = $db->query('SELECT * FROM members');
    while($row = $result->fetchArray()) {
        $xml_member = $xml->createElement("Member");
        $name_attribute = $xml->createAttribute('Name');
        $name_attribute->value = $row['name'];
        $xml_member->appendChild($name_attribute);
        $age_attribute = $xml->createAttribute('Age');
        $age_attribute->value = $row['age'];
        $xml_member->appendChild($age_attribute);
        $xml_info->appendChild($xml_member);
    }
    $xml->appendChild( $xml_info );
    $xml->save("members.xml"); 
    $db->close();
    print $xml->saveXML();
    //// I tried the following lines with no luck
    // $file = file_get_contents('club-members.xml');
    // echo htmlspecialchars($file, ENT_QUOTES);
?>

如何从PHP发送XML

问题描述

1 个解决方案

解决方案1
0 已采纳 2016-12-09 00:48:57

如何从PHP发送XML

问题描述

1 个解决方案

解决方案1 0 已采纳 2016-12-09 00:48:57

解决方案1
0 已采纳 2016-12-09 00:48:57