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Java JSON当type为String或List时反序列化<String>

[英]Java JSON Deserialize when type is String or List<String>

Is there a simple way to deserialize a value that may be either a String or a List<String> ? 是否有一种简单的方法来反序列化可能是StringList<String>

I have to process a large JSON that I'll abbreviate like: 我必须处理一个我将缩写为的大型JSON:

{"A": {"item1": 1,
        ...
       "itemN": "SomeString",
        ...
       "itemM": 123.45},
 "B": { ... },
 "C": { ... },
 }

And sometimes it looks like this: 有时它看起来像这样:

{"A": {"item1": 1,
        ...
       "itemN": ["SomeString1", "SomeString2"],
        ...
       "itemM": 123.45},
 "B": { ... },
 "C": { ... },
 }

I deserialize with: 我反序列化:

MyData data = new Gson().fromJson(rxJSON, DataClass.class);

Where DataClass: DataClass的位置:

@Parcel
public class DataClass {
    @SerializedName("A")
    private AClass groupA;
    @SerializedName("B")
    private BClass groupB;
    @SerializedName("C")
    private BClass groupC;
    ... getters/setters ...
}

and AClass: 和AClass:

@Parcel
public class AClass {
    @SerializedName("item1")
    private int item1;
    ...
    @SerializedName("itemN")
    private List<String> itemN;
    ...
    @SerializedName("itemM")
    private float itemM;
    ... getters/setters ...
}

Ideally, I'd like to use AClass for both JSONs, and in the case where itemN is a String , simply treat it as if it were a single element List<String> (ie. treat "SomeString" as ["SomeString"] ). 理想情况下,我想对两个JSON使用AClass ,并且在itemNString的情况下,只需将它视为单个元素List<String>"SomeString"视为["SomeString"] )。 After deserializing, I always want to access it as a list for simplicity in the rest of my code. 反序列化后,我总是希望在其余代码中将其作为简单列表进行访问。

I've seen suggestions for Polymophism solutions and solutions suggesting attempting to deserialize with one version of a class assuming one type (such as String ) and in an exception catch deserialize with a version of the class assuming the other type (such as List<String> ). 我已经看到了对Polymophism解决方案和解决方案的建议,建议尝试使用一个类的一个版本(如String )反序列化,并在异常中使用假定其他类型的类的版本反序列化反序列化(例如List<String> )。 Other solutions suggest a more manual/piece-wise deserialization where it would deserialize only one level of the JSON hierarchy at a time until I came to itemN and then check it's type. 其他解决方案建议更多手动/分段反序列化,它一次只反序列化JSON层次结构的一个级别,直到我来到itemN然后检查它的类型。 It seems like there should be a simpler way. 似乎应该有一个更简单的方法。 Is there? 在那儿?

I found a good solution thanks to: https://stackoverflow.com/a/31563539/3571110 and https://stackoverflow.com/a/6205384/3571110 我找到了一个很好的解决方案,感谢: https//stackoverflow.com/a/31563539/3571110https://stackoverflow.com/a/6205384/3571110

The first link shows using a custom deserializer for the entire JSON (too much work for me), and within that manages String to List<String> . 第一个链接显示为整个JSON使用自定义反序列化器(对我来说太多工作),并在其中管理String to List<String> The second link gave me the insight that I could make a custom deserializer for basic types like List<> (I previously thought I could only use custom classes). 第二个链接让我了解了我可以为List<>等基本类型创建自定义反序列化器(我之前认为我只能使用自定义类)。 Combining those ideas and making the appropriate changes yields (everything else staying the same): 结合这些想法并做出适当的改变(其他一切保持不变):

Solution: 解:

public class ListOrStringDeserializer implements JsonDeserializer<List<String>> {

    @Override
    public List<String> deserialize(JsonElement json, Type typeOfT,
                                    JsonDeserializationContext context) 
            throws JsonParseException {

        List<String> items = Collections.emptyList();
        if (json.isJsonArray()) {
            items = context.deserialize(json, List.class);
        } else if (json.isJsonPrimitive()) {
            items = Collections.singletonList((String) context.deserialize(json, String.class));
        }
        return items;
    }
}

Then register before deserializing: 然后在反序列化之前注册:

Gson gson = new GsonBuilder().registerTypeAdapter(new TypeToken<List<String>>() {}.getType(), new ListOrStringDeserializer()).create();
MyData data = gson.fromJson(rxJSON, DataClass.class);

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