从自定义字符串中提取十六进制代码数据

Question

For example we put the following string: #FF00FFNick#AA00efName

I want to create a pattern to get the following output array

{ [0] = {"#FF00FF", "Nick"}, [1] = {"#AA00ef", "Name"} }

I write the following code

 var reg = /#([a-f\d]{3}){1,2}(.*?)/gi;

 alert(str.match(reg));

But the output i get only hex-code substrings. Where is the mistake?

Answer 1

I suggest

/(#(?:[a-f\d]{3}){1,2})([^#]+)/gi

See the regex demo

Details :

• (#(?:[af\\d]{3}){1,2}) - Group 1 capturing
  • # - a hash symbol
  • (?:[af\\d]{3}){1,2} - 1 or 2 sequences of hex chars (case insensitive due to i modifier)
• ([^#]+) - Group 2 capturing 1+ chars other than # .

Demo:

 var s = "#FF00FFNick#AA00efName"; var re = /(#(?:[af\\d]{3}){1,2})([^#]+)/gi; var res = [], m; while ((m=re.exec(s)) !== null) { res.push([m[1], m[2]]); } console.log(res);