JavaScript：正则表达式为一个字母和一个点

Question

Using Javascript, I am trying to split a text using a regular expression that contains only one letter and a point; for example 'A.' or 'Q.' I am using: array[0].split(/[AZ]+./); But it is returning true if there are multiple characters like 'AA.' or 'ZZ.'

What is the regex for one character only? I also have access to jQuery.

Thank you!

Answer 1

This should work: array[0].split(/([AZ]{1}\\.)/);

Explanation:
[AZ]{1} - this looks for any single letter
\\. - this looks for a . note that you'll need the backslash as a . in a regex means any character.
These are surrounded by brackets so that you are looking for the sequence: one letter followed by a .

You'll need to remove the + as it means one or more. if you want to find several occorances then you'll need the global flag (g at the end): array[0].split(/([AZ]{1}\\.)/g);

Limit to A. and not AA.
If you want to make sure its only one letter follow by a . and not match on the end of AA. then you can use the word boundary like so: array[0].split(/\\b([AZ]{1}\\.)/);

This site is amazing for helping with regex: https://regex101.com/

Answer 2

You don't want to use + , as it means "one or more". Just remove it. Also you have to escape the . otherwise it means "any character".

If you want to match only a capital letter and a point, this should do the trick : /[AZ]\\./g if you want the regex to be case insensitive, simply add the i flag : /[AZ]\\./gi . Remove the g flag if you only want to match the first occurrence.

Answer 3

你可以试试这个

/\s[A-Z]\.\s/g