使用malloc为数组分配内存

Question

I'm trying to make an array of structs by using malloc to allocate the memory needed like so:

typedef struct stud{
   char stud_id[MAX_STR_LEN];
   char stud_name[MAX_STR_LEN];
   Grade* grd_list;
   Income* inc_list;
}Stud;

Stud* students = malloc(sizeof(Stud)*STUDENT_SIZE);

The problem is that I have a function that adds id and name to a place in the array like so:

void new_student(Stud* students[], int stud_loc){
   scanf("%s", students[stud_loc]->stud_id);
   printf("%s", students[stud_loc]->stud_id);
   scanf("%s", students[stud_loc]->stud_name);
   printf("%s", students[stud_loc]->stud_name); 
}

But after the first call to the function, which works, the second one gives me the error:

Segmentation fault (core dumped)

And I can only think that it must mean I'm not doing this right and all the memory is probably going into one place and not in an array form. I'd rather do

  Stud students[STUDENT_SIZE];

but in this case I must use malloc.

I tried using calloc but I still get the same error.

Answer 1

There's a mismatch between the local variable Stud *students and the function parameter Stud *students[] . Those two variables ought to have the same type.

The local variable and malloc() look good. new_student has an undesirable extra layer of pointers. It should look like this instead:

void new_student(Stud* students, int stud_loc){
   scanf ("%s", students[stud_loc].stud_id);
   printf("%s", students[stud_loc].stud_id);
   scanf ("%s", students[stud_loc].stud_name);
   printf("%s", students[stud_loc].stud_name); 
}

You would then call it like so:

Stud* students = malloc(sizeof(Stud)*STUDENT_SIZE);

new_student(students, 0);
new_student(students, 1);
new_student(students, 2);