[英]Making a word Scrambler with Math.random
import java.util.Scanner;
public class WordScrambler {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int chosenWord;
String[] words = {"hogwash","Rudolph","yule-log","Eggnog","CandyCane","Christmas","Fruitcake","gingerbread","Krampus","nutcracker"};
System.out.println("Pick a number between 1-10");
chosenWord=in.nextInt();
String a=words[chosenWord].substring(0,words[chosenWord].length()/2);
String b=words[chosenWord].substring(words[chosenWord].length()/2);
String c=b+a;
int x=(int)(Math.random()*(words[chosenWord].length()-1))+1;
String d=c.substring(0, words[chosenWord].length()-x);
String e=c.substring(words[chosenWord].length()-x);
String f=e+d;
System.out.println(f);
}
}
This is what i have so far. 这是我到目前为止所拥有的。 I cant find a way to Scramble it anymore.
我再也找不到加扰的方法了。 Right now the output is for example: Hogwash :shhogwa.
现在的输出例如是:Hogwash:shhogwa。 Thats the only word that Scrambles.
多数民众赞成在唯一的单词。
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int chosenIndex;
String[] words = { "hogwash", "Rudolph", "yule-log", "Eggnog", "CandyCane", "Christmas", "Fruitcake",
"gingerbread", "Krampus", "nutcracker" };
System.out.println("Pick a number between 1-10");
chosenIndex = in.nextInt();
String chosenWord = words[chosenIndex - 1];
System.out.println(chosenWord);
StringBuilder scrambled = new StringBuilder();
List<Character> letters = new ArrayList<Character>();
for (char x : chosenWord.toCharArray()) {
letters.add(x);
}
while (letters.size() != 0) {
int random = (int) (Math.random() * letters.size());
scrambled.append(letters.remove(random));
}
System.out.println(scrambled.toString());
}
use meaningful variable names so its clear what its referring to 使用有意义的变量名,以便清楚地指出其指的是什么
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