[英]Using 3D style slicing in a 2D numpy array
I have a function that takes a numpy array (A) as input. 我有一个函数,需要一个numpy数组(A)作为输入。 This array could be a 2d or a 3d array depending on a mathematical calculation.
根据数学计算,此数组可以是2d或3d数组。 There is an integer m which could be any number, except when the array is 2D, the value of m will always be 0. I want to pass a silce of A to another function.
有一个整数m,该整数可以是任意数字,但当数组为2D时,m的值将始终为0。我想将A的silc传递给另一个函数。 Since A can be both 3D or 2D, I tried 3D style slicing.
由于A可以是3D或2D,因此我尝试了3D样式切片。
def fun(A):
... some code
ans = fun2(A[:,:,m]) #The value of m is 0 if A is 2D
This gives me an IndexError
when A is 2D 当A为2D时,这给我一个
IndexError
IndexError: too many indices for array
I want to pass the full 2D array to fun2 if A is 2D, like it happens in MATLAB. 如果A是2D,我想将完整的2D数组传递给fun2,就像在MATLAB中一样。 How can it be done in Python?
如何在Python中完成? I use Python 2.
我使用Python 2。
Seems like a good setup to use np.atleast_3d
as we can force it to be 3D
and then simply slice the m-th index along the last axis, like so - 似乎是使用
np.atleast_3d
的好设置,因为我们可以将其强制为3D
,然后简单地沿最后一个轴切片第m个索引,如下所示-
np.atleast_3d(A)[...,m] # Or np.atleast_3d(A)[:,:,m]
It's still a view into the array, so no efficiency lost there! 它仍然是阵列的视图,因此不会损失任何效率!
Case runs 案例运行
1) 2D : 1)2D:
In [160]: A = np.random.randint(11,99,(4,5))
In [161]: np.atleast_3d(A)[...,0]
Out[161]:
array([[13, 84, 38, 15, 26],
[64, 91, 29, 11, 48],
[25, 66, 77, 14, 87],
[59, 96, 98, 30, 88]])
In [162]: A
Out[162]:
array([[13, 84, 38, 15, 26],
[64, 91, 29, 11, 48],
[25, 66, 77, 14, 87],
[59, 96, 98, 30, 88]])
2) 3D : 2)3D:
In [163]: A = np.random.randint(11,99,(4,3,5))
In [164]: np.atleast_3d(A)[...,1]
Out[164]:
array([[34, 81, 66],
[56, 20, 25],
[45, 36, 64],
[82, 64, 31]])
In [165]: A[:,:,1]
Out[165]:
array([[34, 81, 66],
[56, 20, 25],
[45, 36, 64],
[82, 64, 31]])
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