[英]How to get parameter in url (laravel 5.3)?
My url is like this : http://localhost/mysystem/public/users/index/2016
我的网址是这样的:
http://localhost/mysystem/public/users/index/2016
I want to get 2016
, because I need it. 我想要
2016
,因为我需要。 But, I'm confused 但是,我很困惑
Is there any people who can help me? 有没有人可以帮助我?
In your previous question I can see this method: 在您之前的问题中,我可以看到此方法:
public function store(CreateUserRequest $request)
And your route should look like this (partially taken from previous answer too): 而且您的路线应如下所示(也部分取自之前的答案):
Route::get('users/store/{year}', 'UserController@store')->name('users.store.year');
Note, that if you'll build store
method with Route::resource()
, you'll not be able to pass year through URL. 请注意,如果要使用
Route::resource()
构建store
方法,将无法通过URL传递年份。
So, to make it work you need to set route and to change method to this: 因此,要使其正常工作,您需要设置路由并更改此方法:
public function store(CreateUserRequest $request, $year)
$year
variable will have 2016
value. $year
变量的值将为2016
。
To get 2016
, you can use $year = Request::segment(3);
要获得
2016
,可以使用$year = Request::segment(3);
. 。
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