[英]STM8SF103 Assembly - Load immediate value to ram register
I am trying to write a program in assembly language for the stm8sf103
microcontroller. 我正在尝试用汇编语言为
stm8sf103
微控制器编写程序。 I would like to store an immediate hexadecimal value in a ram register (such as $0), but this isn't working and i am wondering why: 我想将一个立即数十六进制值存储在ram寄存器中(例如$ 0),但这不起作用,我想知道为什么:
stm8/
segment 'rom'
loop
ld $0,#5
jp loop
end
I get the error: 我得到错误:
as1 : Error 54: Can't match Addressing mode ' ld $0,#5'
Use 采用
MOV $0, #5
The instruction doesn't affect any condition flag. 该指令不影响任何条件标志。
From the ST8 Programming Manual , the description of MOV
is 从ST8编程手册中 ,
MOV
的描述为
Moves a byte of data from a source address to a destination address.
将数据字节从源地址移动到目标地址。 Data is examined as it is moved 1 .
数据在移动时会被检查1 。 The accumulator is not affected.
累加器不受影响。
There are 3 addressing modes for the
MOV
instruction:MOV
指令有3种寻址模式:
- An immediate byte to a direct memory location
立即字节到直接存储位置
- A direct memory location to another direct memory location (from $00 to $FF)
直接存储位置到另一个直接存储位置(从$ 00到$ FF)
- A direct memory location to another direct memory location (from $0000 to $FFFF)
直接存储位置到另一个直接存储位置(从$ 0000到$ FFFF)
You can refer to that manual for the supported addressing modes (20 in total), so you can understand why ld $0,#5
cannot work (there is no Direct with Immediate addressing). 您可以参考该手册以了解受支持的寻址模式(总共20种),因此您可以理解为什么
ld $0,#5
无法工作(没有直接寻址和直接寻址)。
1 I can't understand this phrase, I believe there is a typo (it should be Data is not examined ... ). 1我听不懂这句话,我相信有一个错字(应该是未检查数据... )。 The manual clearly states that no flag is affected.
该手册明确指出没有标志受到影响。
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