忽略本地时区的角度的日期选择器

Question

Is there any date picker that just displays what is supplied to it and ignores the local timezone?

We're currently using angular-strap 's date picker and the data-min-date changes when the local time zone of the computer is changed. The supplied data-min-date is just a fixed date but somehow the date picker is affected by the local time zone.

Example:

Supplied Date: 2016-12-23T16:33:03+08:00 ISO8601 Format

On UTC-12:00 22-December-2016 is disabled so the minimum is 23-December-2016 .

On UTC+08:00 23-December-2016 is disabled so the minimum is 24-December-2016 .

Not sure which one is the expected date, but the expected outcome should be that there will be no changes since a fixed date is supplied.

Is there anything I am missing or any other calendar that will just display what is given to it?

EDIT 1 : Is it a legit way to test date functionalities by changing the local timezone of a computer? Is it the same or different than when you are locally or naturally situated in that timezone?

EDIT 2 : We already generated datetime from our node server using momentjs . var serverTime = moment().utcOffset(8); it's just the the angular-strap handles the date we supplied in an odd way.

EDIT 3 : Adding an attribute data-timezone="utc" doesn't help either.

EDIT 4 : We've discovered that the plug-in uses date = new Date(value); in which value is the date that we passed. And it returns something like Thu Dec 22 2016 21:29:54 GMT-1200 (Local Standard Time) which clearly uses the local timezone. And there is no condition to check if there is timezone="utc" supplied. We also tried to directly assign date = Thu Dec 22 2016 21:29:54 GMT-1200 (Local Standard Time) but the plug-in breaks.

Answer 1

We did a hack around. We forked the plug in and changed the code that handles the min-date .

Change history can be found here . Snippet we added:

var a = new Date(value); // value - date we are passing
var b = a.getTime() + (a.getTimezoneOffset() * 60000); // no idea what this is
date = new Date(b + (3600000*(8))); // the 8 is the timezone we want

The problem with the new Date(value) is that it is affected by the local timezone.