jQuery从全选中排除复选框

Question

My HTML code to select all checkboxes

Select All <input type="checkbox"  name='select_all' id='select_all'  value='1'/>

My Javascript code to select all checkboxes

<script type="text/javascript">
    $('#select_all').change(function() {
    var checkboxes = $(this).closest('form').find(':checkbox');
    if($(this).is(':checked')) 
    {
       checkboxes.prop('checked', true);
                } else {
        checkboxes.prop('checked', false);
        }
    });
    </script>

The code works great and selects all the checkboxes, I would like to exclude the following checkbox from the selection (select all) criteria, is it possible to exclude the following?

 <input type="checkbox"  name='sendtoparent' id='sendtoparent'  value='1'/>

Answer 1

尝试使用not方法：

$(this).closest('form').find(':checkbox').not('#sendtoparent');

Answer 2

Firstly you can use :not or not() to exclude the element by its id attribute. From there you can simplify the logic by just setting the checked property of those checkboxes to match that of the #select_all element. Try this:

$('#select_all').change(function() {
  var $checkboxes = $(this).closest('form').find(':checkbox').not('#sendtoparent');
  $checkboxes.prop('checked', this.checked);
});