Firebase查询等于在Swift中不返回值

Question

I have a Firebase structure that looks like:

- key1
  -key2
     -key3:value
     -key4:value
     -key5:value
     -key6:value

I am looking to return records where key3 's value equals a particular string.

let ref = FIRDatabase.database().reference()
let path = "Object/key1/key2"

ref.child(path).queryOrdered(byChild: "key3").queryEqual(toValue: "myvalue").observeSingleEvent(of: .value, with: {(snapshot) in

The above returns NULL. If I remove the queryEqual , all records are returned. I have triple checked that the "myvalue" is matching in FB as well as in the call.

I have the FB call in a loop as key1 and key2 change. In the end I only want those records (everything under key2 ) returned only if key3 is equal to value I send in my queryEqual statement.

To give the full return see below. I commented out my actual return process to just check via a simple print:

ref.child(path).queryOrdered(byChild: "key3").queryEqual(toValue: "mvValue").observeSingleEvent(of: .value, with: {(snapshot) in

            for test in snapshot.children
            {
                print (test)
            }

            /*if let returnDict = snapshot.value as? NSDictionary
            {
                helperProtocol.firebaseDidReturn?(returnDict: returnDict, extraDict: extraDict, name:name)
            }
            else if let returnArray = snapshot.value as? NSArray
            {
                helperProtocol.firebaseDidReturn?(returnDict: ["array":returnArray], extraDict: extraDict, name:name)
            }
            else
            {
                helperProtocol.firebaseDidReturn?(returnDict: nil, extraDict: extraDict, name:name)
            }*/
        })

Answer 1

The issue was the depth of the query path. From the above I was using:

let path = "Object/key1/key2"

The path needed to be:

let path = "Object/key1"

So even though the search key ( key3 ) is under key2 , the approach is to go one level higher as shown above.