如何使用Python的re.sub匹配和替换组零次或多次？

Question

import re
host = 'www.example.com'
urls = [
'auth_redirect_url = aaa.bbb.ccc.com/auth-web',
'auth_redirect_url = aaa.bbb.ccc.com'
]    
for url in urls:
    print re.sub(r'(^auth_redirect_url\s*=\s*)(.*)(/.*)', r'\g<1>{}\g<3>'.format(host), url)

I want to replace the host name 'aaa.bbb.ccc.com' to 'www.example.com', but the regex does not work, because the path in url may not exist. Is there a way to match a group 0 or more times? Or how to deal with this problem?

Answer 1

此方法可能对您有帮助

text_filtered = re.sub(r'<p ([^>]*)>', '<p>', text_filtered) # remove the other field from p tag

Answer 2

Your second group could capture everything except / :

import re

host = 'www.example.com'
urls = [
    'auth_redirect_url = aaa.bbb.ccc.com/auth-web',
    'auth_redirect_url = aaa.bbb.ccc.com'
]

for url in urls:
    print re.sub(r'(^auth_redirect_url\s*=\s*)([^/]*)(.*)',
                 r'\g<1>{}\g<3>'.format(host), url)

Output:

auth_redirect_url = www.example.com/auth-web
auth_redirect_url = www.example.com