如何将多行从一个表转移到另一个表 (SQL)

Question

I have two tables TableA and TableB with colums id , login , pass . Also I have a php array: $array = [1,3,5] . How can I transfer rows from TableA to TableB where id equal each value of my array? id is autoincremented and must be unique. In my head it looks like this :

INSERT INTO TableB (`login`, `pass`) 
SELECT `login`, `pass` FROM TableA WHERE `id` = $array[0] 
AND `id` = $array[1] AND `id` = $array[2];

But it does not work

Is there any chances to do it in cycle using WHILE ?

Answer 1

You can use a statement such as this:

$ids = [1,3,5];
$query = "INSERT INTO `TableB` (`login`, `pass`) SELECT `login`,`pass` FROM `TableA` WHERE `id` IN (".implode(",", $ids).");";

Although: You should be using prepared statements and parameters for this, this answer is just meant to show the syntax.

Answer 2

it is easy let's say you are using mysqli:

$query= "SELECT * FROM TableA limit 3";
//takes first 3 rows from TableA
//$con being the connection string in config file
$result = mysqli_query($con,$query);
while($row = mysqli_fetch_array($result)){
//takes each row by row
$username = $row['username'];
$password = $row['password'];
//now that we initiated variables the sql query
$query1 = "INSERT INTO TableB (username, password) VALUES ('$username', '$password')";
mysqli_query($con,$query1);
}

Hope this helps

EDIT: I just read that it should have an array so you should change your query to this:

for($i=0; $i<count(array), $i++){

$query= "SELECT * FROM TableA WHERE ID = '$array[i]'";

//$con being the connection string in config file
$result = mysqli_query($con,$query);
while($row = mysqli_fetch_array($result){
//takes each row by row
$username = $row['username'];
$password = $row['password'];
//now that we initiated variables the sql query
$query1 = "INSERT INTO TableB (username, password) VALUES ('$username', '$password')";
mysqli_query($con,$query1);
}
}