Neo4j中的Cypher Where IN ['GUID'，'GUID']

Question

I am trying to find nodes in Neo4j Db by Guid from my object. 我试图从我的对象中找到Guid在Neo4j Db中的节点。

I have 'Id' field in my object, which is Guid. 我的对象是Guid，其中包含“ Id”字段。 Need to find several nodes by those Guid Id, but when I use Where clause and use IN command with array of Guid Id's I get response, that (no changes, no records) 需要通过那些Guid Id查找几个节点，但是当我使用Where子句并将IN命令与Guid Id的数组一起使用时，我会得到响应，（没有更改，没有记录）

MATCH (n) WHERE n.Id IN ['44BEE918-507A-15C6-0950-0017D4A12234', 'BC2D286F-0B73-6926-B01D-27C8F0EA919D'] RETURN n LIMIT 25

I tried to pass Guids without quotes and with double quotes, but it didn't help. 我试图通过不带引号和双引号的Guid，但这没有帮助。 When I pass the Name of those nodes it works perfect. 当我传递这些节点的名称时，它可以正常工作。 What I am doing wrong? 我做错了什么？

Answer 1

I found an issue. 我发现了一个问题。 The problem was with case sensitivity. 问题在于区分大小写。 Means my Guid in the database looks like '44bee918-507a-15c6-0950-0017d4a12234', but I tried to find in upper case. 意味着我在数据库中的Guid看起来像是'44bee918-507a-15c6-0950-0017d4a12234'，但是我尝试用大写字母查找。

Neo4j中的Cypher Where IN ['GUID'，'GUID']

问题描述

1 个解决方案

解决方案1
0 2016-12-27 08:56:42

Neo4j中的Cypher Where IN [&#39;GUID&#39;，&#39;GUID&#39;]

问题描述

1 个解决方案

解决方案1 0 2016-12-27 08:56:42

Neo4j中的Cypher Where IN ['GUID'，'GUID']

解决方案1
0 2016-12-27 08:56:42