[英]Why my implemented_function() results in NameError: global name 'Derivative' is not defined?
Why does this code 为什么这个代码
user_f = lambda a, b: a + b
user_x = lambda u: 2 * u
import sympy
from sympy.abc import t
from sympy.utilities.lambdify import implemented_function
x = implemented_function(sympy.Function('x'), user_x)
f = implemented_function(sympy.Function('f'), user_f)
dx = sympy.diff(f(x(t), t), t, 1)
print(dx)
fl = sympy.lambdify((x(t), t), dx)
print(fl(x(t), t))
give me the output below? 给我下面的输出? (Shouldn't it have sufficient information to fully evaluate the derivatives?)
(它不应该有足够的信息来全面评估衍生品吗?)
How do I fix (or work around) this error? 如何修复(或解决)此错误? Assume I am given
user_f
and user_x
as inputs. 假设我被赋予
user_f
和user_x
作为输入。
Derivative(x(t), t)*Subs(Derivative(f(_xi_1, t), _xi_1), (_xi_1,), (x(t),)) + Subs(Derivative(f(x(t), _xi_2), _xi_2), (_xi_2,), (t,))
Traceback (most recent call last):
File <path>, line 12, in <module>
print(fl(x(t), t))
File "<string>", line 1, in <lambda>
NameError: global name 'Derivative' is not defined
Providing the modules
argument of sympy.lambdify()
eliminates the problem: 提供
sympy.lambdify()
的modules
参数可以解决问题:
>>> fl = sympy.lambdify((x(t), t), dx, modules=sympy)
>>> print(fl(x(t), t))
Derivative(x(t), t)*Subs(Derivative(_xi_1 + t, _xi_1), (_xi_1,), (x(t),)) + Subs(Derivative(_xi_2 + x(t), _xi_2), (_xi_2,), (t,))
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