[英]LINQ for dynamic columns in a table in c#
You can build lambda expression dynamically by using System.Linq.Expression
namespace and pass it to Where
method. 您可以使用
System.Linq.Expression
命名空间动态构建lambda表达式,并将其传递给Where
方法。
For example: 例如:
public IQueryable<Vehicle> GetAccounts(string variant)
{
// Build equivalent lambda to 'param => param.{variant} == "Y"'
// This is lambda parameter
var param = Expression.Parameter(typeof(Vehicle));
// This is lambda body (comparison)
var body = Expression.Equal(
// Access property {variant} of param
Expression.Property(param, typeof(Vehicle).GetProperty(variant)),
// Constant value "Y"
Expression.Constant("Y")
);
// Build lambda using param and body defined above
var lambda = Expression.Lambda<Func<Vehicle, bool>>(body, param);
// Use created lambda in query
return VehicleDatatable.Where(lambda);
}
Another idea is to convert query a bit. 另一个想法是将查询转换一下。 You can realize same work using following query:
您可以使用以下查询来实现相同的工作:
sQuery = "Select * from Vehicle where (Tracks+Cars+Utility) LIKE '" + value + "'";
Where value
is 'Y__' or ' Y ' or '__Y' depending on which vehicle type you want to query. 根据要查询的车辆类型,
value
是“ Y__”或“ Y ”或“ __Y”。 It's definitely not most effective, but that is pretty easy to convert to linq. 绝对不是最有效,但这很容易转换为linq。
Build your query: 建立您的查询:
var query = Vehiclelist;
if (column == "Trucks")
{
query = query.Where(q => q.Trucks=="Y");
}
else if (column == "Cars")
{
query = query.Where(q => q.Cars=="Y");
}
else if (column == "Utility")
{
query = query.Where(q => q.Utility=="Y");
}
This approach is more maintainable, more testable. 这种方法更可维护,更可测试。 You have strong-typed expressions and transparent filters.
您具有强类型表达式和透明过滤器。
尝试这个:
Vehiclelist.Where(q => q.Trucks=="Y" || q.Cars=="Y" || q.Utility=="Y");
using lambda expression : 使用lambda表达式:
VehicleDatatable.AsEnumerable().Where(q=>q.Trucks=="Y" || q.Cars=="Y" || q.Utility=="Y");
Another way 其他方式
(from d in VehicleDatatable.AsEnumerable() where string.compare(d["Trucks"],"Y")==0 select d)
This may also be another approach: 这也可能是另一种方法:
PropertyInfo pi = typeof(Vehicles).GetProperty(vehVariant);
var services = context.Vehicles.ToList();
services = services.Where(item => pi.GetValue(item).ToString().Trim() == "Y").ToList();
Happy Coding. 编码愉快。
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