返回查找查询中的整个文档-Mongodb

Question

Assume I have document as;

{
  id: 1,
  name: "alex",
  adress: [
    {type: "home" , street: "flower"},
    {type: "business" , street: "falls"},
    {type: "xxx" , street: "xxx"},
  ]
}

I want to get home adress. In order to get this, I wrote the following query;

db.collection.find({id: 1, "adress.type" : "home"})

As a result of this query it returned me;

{
  id: 1,
  name: "alex",
  adress: [
    {type: "home" , street: "flower"},
    {type: "business" , street: "falls"},
    {type: "xxx" , street: "xxx"},
  ]
}

However what I want is to get only home adress ;

{
  id: 1,
  name: "alex",
  adress: [
    {type: "home" , street: "flower"}
  ]
}

How can I narrow the result of this query? How should I wrote the query in order to get only the home adress ?

---

edit after trying the answers from @SagarReddy and @suzo. Their answers are correct if I have one match.

The answers are not applicable in the following case;

{
  id: 1,
  name: "alex",
  adress: [
    {type: "home" , street: "flower"},
    {type: "business" , street: "falls"},
    {type: "home" , street: "instinct"},
    {type: "xxx" , street: "xxx"},
  ]
}

db.collection.find({id: 1, "adress.type" : "home"}, {"adress.$":1}) returns;

{ 
    id: 1
    "adress" : [
        {
            "type" : "home", 
            "street" : "flower"
        }
    ]
}

which is not true. It gets only one match.

What do you I expect is;

{ 
"id" : 1, 
"name" : "alex", 
"adress" : [
    {
        "type" : "home", 
        "street" : "flower"
    }, 
    {
        "type" : "home", 
        "street" : "instinct"
    }
]

}

So question is still valid. How can I get only the matched parts in mongodb find query?

Answer 1

You can use positional $ operator to limit the contents of an array from the query results to contain only the first element matching the query document like below :

db.collection.find({id: 1, "adress.type" : "home"}, {"name":1, "address.$":1});

But use $ in the projection document of the find() method or the findOne() method when you only need one particular array element in selected documents.

To get all the matched elements in the array instead of the first element only, you can use $filter aggregator to do that like below :

This is New in Mongodb version 3.2.

[{
 "$match": {
   "address.type": "home"
 }
},
{
"$project": {
  "address": {
    "$filter": {
      "input": "$address",
      "as": "address",
      "cond": {
        "$eq": ["$$address.type", "home"]
      }
    }
  }
}
}]

Answer 2

try aggregation match and project the address.

 db.collection.aggregate([
                  { $match : {id: 1, "adress.type" : "home"}},
                  {$project : { adress: 1} } 
                   ]}.exec(function (err, doc) {
        if (err) callback(err);
        else callback(null, doc);
    });