[英]How to check if constant is defined, inside function - php
I am trying to make a small PHP function which can check if a constant is defined, and if so, echo it, and if not, echo space or nothing. 我正在尝试制作一个小的PHP函数,该函数可以检查是否定义了常量,如果定义了常量,则回显它,如果没有,则回显空格或什么也没有。
Right now, the if(defined()
part is not working, because the constant is being transferred to a variable inside the function. 现在,
if(defined()
部分不起作用,因为常量正在被传递到函数内部的变量中。
function getConstant($constant) {
if(defined($constant)) {
echo constant($constant);
} else {
echo '';
}
}
The echo constant($constant)
part is working fine, but I cannot check if the constant is actually defined because it is a variable now. echo constant($constant)
部分工作正常,但是我无法检查该常量是否已实际定义,因为它现在是一个变量。
I cannot seem to find a solution for it 我似乎找不到解决方案
public static function isConstants($constant) {
$oClass = new ReflectionClass(__CLASS__);
$allConstants = $oClass->getConstants();
if (isset($allConstants[$constant])) {
echo $allConstants[$constant];
} else {
echo '';
}
}
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