在 python 中基于列表理解的条件跳过元素

Question

I have a list List:

List = [-2,9,4,-6,7,0,1,-4]

For numbers less than zero (0) in the list, I would like to skip those numbers and form another list.

Example:-

List = [9,4,7,0,1]

This is a kind of doubt I have, not sure If we can achieve. If it's possible to achieve, can anyone please post here.

Answer 1

You have many options to achieve that. With a list comprehension you can do:

my_list = [i for i in my_list if i>=0]

With filter() :

my_list = filter(lambda i: i>=0, my_list)

Note:

In Python 3, filter() returns a filter object (not list ), to convert it to a list, you can do:

my_list = list(filter(lambda i: i>=0, my_list))

Answer 2

First use lower case for variable names, second don't use list because it reserved name.

Then just do an if inside the list comprehension

my_list = [i for i in init_list if i >= 0 ]

Answer 3

I have tried this code here my_list = [i for i in init_list if i >= 0 ] but i had modified it to fit to my use and i would like to say that it can be used like this:

for i in [x for x in range(10) if != 3] 

I used it here to make the program skip a iteration.