使用带有regexp（json字符串）的特定值从mysql获取行

Question

I'm storing permissions into DB with Array JSON String, and i want select them by permission specific permission. at this time I'm selecting them like this:

  1 | Dog   | [3,4]
  2 | Cat   | [33,4]
  3 | Tiger | [5,33,4]
  4 | wolf  | [3,5]


 SELECT * FROM `pages` WHERE access REGEXP '([^"])3([^"])'

it works but not as it should work. This query gives me all records which contains 3 but also it gives which contains 33. my question is how i must format my regexp to get row by specific value into json string.

ps i have mysql 5.5 so as i know on this version json functions is not supported

Answer 1

如果字段中仅包含数字，则可以将正则表达式更改为仅在要查找的字符串（此处为“ 3”）没有紧邻其的其他数字的情况下采用值：

SELECT * FROM `pages` WHERE access REGEXP '([^"0-9])3([^"0-9])'    

Answer 2

REGEXP '[[:<:]]3[[:>:]]'

也就是说，使用“单词边界”东西。