打开多个选项卡并在shell脚本中执行命令

Question

#!/bin/bash

tab="--tab"
cmd="bash -c 'python';bash"
foo=""

for i in 1 2 3; do
      foo+=($tab -e "$cmd")         
done

gnome-terminal "${foo[@]}"

exit 0

i'm using this scirpt to open multiple tabs using shell script.

call it multitab.sh and execute this way user@user:~$ sh multitab.sh

currently this script supposed to open 3 tabs and all of them will execute python command. but when i execute it, throws en error

multitab.sh: 8: multitab.sh: Syntax error: word unexpected (expecting ")")

What is the reason of this error? How can I make this script to execute 3 different commands?

I've already gone through. below SOF threads but none of them worked for me.

• https://askubuntu.com/questions/315408/open-terminal-with-multiple-tabs-and-execute-application
• https://askubuntu.com/questions/500357/opening-multiple-terminal-tabs-and-running-command
• https://askubuntu.com/questions/521084/bash-script-for-multiple-tabs-program-running

Answer 1

This is because you are running the script with sh , where the += syntax to add elements is not available:

foo+=($tab -e "$cmd")
#  ^^

So all you need to do is to run the script with Bash:

bash multitab.sh

Or just using ./multitab.sh (after giving executing mode to the file), since the shebang in the script ( #!/bin/bash ) already mentions Bash.

From the Bash Reference Manual:

Appendix B Major Differences From The Bourne Shell

- Bash supports the '+=' assignment operator, which appends to the value of the variable named on the left hand side.