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Drupal 8 Twig模板-如果节点具有菜单项，则显示菜单

[英]Drupal 8 Twig Template - Show menu if node has a menu item

原文 2017-01-05 19:09:50 8 1 menu/ twig/ drupal-8

I am creating custom twig templates for a Drupal 8 theme. 我正在为Drupal 8主题创建自定义树枝模板。 I want to render a menu in a region only if the node has a menu link (ie when editing the node the menu settings on the right has been configured so the “provide a menu link” box has been checked). 我只想在节点具有菜单链接的情况下才在区域中渲染菜单（即，在编辑节点时，已经配置了右侧的菜单设置，因此已选中“提供菜单链接”框）。

Ideally I would like to create this in the twig template so I can change the layout accordingly, but any pointers greatly appreciated! 理想情况下，我想在树枝模板中创建它，以便我可以相应地更改布局，但是任何指针都非常感谢！

1 个解决方案

Usually this issue is handled differently(by creating a separate content type and set visibility) but for the sake of the question I'll give some solutions. 通常，此问题的处理方式不同（通过创建单独的内容类型并设置可见性），但是出于问题的考虑，我将提供一些解决方案。

Solution 1: Block Visibility Groups. 解决方案1：阻止可见性组。

If that is not enough. 如果那还不够。

Solution 2: hook_block_view_alter(or any other hook_ENTITY_TYPE_view_alter) where you can deactivate the access to menu block after you check if condition is met with Drupal::routeMatch() to check what node is displayed. 解决方案2：hook_block_view_alter（或任何其他hook_ENTITY_TYPE_view_alter），在您检查Drupal :: routeMatch（）是否满足条件以检查显示的节点后，可以在其中停用对菜单块的访问。