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如何比较小时和分钟

[英]How to compare hours and minutes

I would like to check if the user has logged into site on time or late suppose the user have to login before 10:15 and he log in at 11:00我想检查用户是否按时或延迟登录网站假设用户必须在 10:15 之前登录并且他在 11:00 登录

how can i just know if he is late or early or on time?我怎么知道他是迟到还是早到或准时?

should i use strtotime ?我应该使用 strtotime 吗?

You can make use of strtotime function which returns the Current Time as a Unix Timestamp.您可以使用 strtotime 函数,该函数将当前时间作为 Unix 时间戳返回。

Compare the two values to check if he/she has logged in late or not.比较这两个值以检查他/她是否延迟登录。

Try this尝试这个

getTimeDifference(10:15,11:00)

 function getTimeDifference($dtime,$atime)
                    {

                     $nextDay=$dtime>$atime?1:0;
                     $dep=EXPLODE(':',$dtime);
                     $arr=EXPLODE(':',$atime);
                     $diff=abs(MKTIME($dep[0],$dep[1],0,DATE('n'),DATE('j'),DATE('y'))-MKTIME($arr[0],$arr[1],0,DATE('n'),DATE('j')+$nextDay,DATE('y')));
                     $hours=FLOOR($diff/(60*60));
                     $mins=FLOOR(($diff-($hours*60*60))/(60));
                     $secs=FLOOR(($diff-(($hours*60*60)+($mins*60))));
                     IF(STRLEN($hours)<2){$hours="0".$hours;}
                     IF(STRLEN($mins)<2){$mins="0".$mins;}
                     IF(STRLEN($secs)<2){$secs="0".$secs;}
                     //RETURN $hours.':'.$mins.':'.$secs;
                     return $hours.':'.$mins;
                    }
$timeString="your time string"

$currTime = strtotime($timeString)
$inTime = strtotime("06/01/2017 11:00AM")

$early=($currTime >= $inTime)

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