Swift 3 '[UIApplicationLaunchOptionsKey : Any]？ 不可转换为 '[String : NSString]'

Question

I have a TVOS app that has been converted form Swift 2 to Swift 3 and I am getting the following error. I am unsure how to silence it.

'[UIApplicationLaunchOptionsKey : Any]?' is not convertible to '[String : NSString]'

It is showing up in this piece of code

appControllerContext.launchOptions["BASEURL"] = AppDelegate.TVBaseURL

        if let launchOptions = launchOptions as? [String: AnyObject] {
            for (kind, value) in launchOptions {
                appControllerContext.launchOptions[kind] = value
            }
        }

ADDED:

 /* Copyright (C) 2015 Hani Hamrouni. All Rights Reserved. */ import UIKit import TVMLKit @UIApplicationMain class AppDelegate: UIResponder, UIApplicationDelegate, TVApplicationControllerDelegate { // MARK: Properties var window: UIWindow? var appController: TVApplicationController? //change the link to your host url static let TVBaseURL = "http://google.com" static let TVBootURL = "\\(AppDelegate.TVBaseURL)js/application.js" // MARK: UIApplication Overrides func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool { // Override point for customization after application launch. window = UIWindow(frame: UIScreen.main.bounds) /* Create the TVApplicationControllerContext for this application and set the properties that will be passed to the `App.onLaunch` function in JavaScript. */ let appControllerContext = TVApplicationControllerContext() /* The JavaScript URL is used to create the JavaScript context for your TVMLKit application. Although it is possible to separate your JavaScript into separate files, to help reduce the launch time of your application we recommend creating minified and compressed version of this resource. This will allow for the resource to be retrieved and UI presented to the user quickly. */ if let javaScriptURL = URL(string: AppDelegate.TVBootURL) { appControllerContext.javaScriptApplicationURL = javaScriptURL } appControllerContext.launchOptions["BASEURL"] = AppDelegate.TVBaseURL if let launchOptions = launchOptions { for (kind, value) in launchOptions { appControllerContext.launchOptions[kind.rawValue] = value as AnyObject } } appController = TVApplicationController(context: appControllerContext, window: window, delegate: self) return true } // MARK: TVApplicationControllerDelegate func appController(_ appController: TVApplicationController, didFinishLaunching options: [String: Any]?) { print("\\(#function) invoked with options: \\(options)") } func appController(_ appController: TVApplicationController, didFail error: Error) { print("\\(#function) invoked with error: \\(error)") let title = "Error Launching Application" //error message let message = error.localizedDescription let alertController = UIAlertController(title: title, message: message, preferredStyle:.alert ) self.appController?.navigationController.present(alertController, animated: true, completion: { () -> Void in // ... }) } func appController(_ appController: TVApplicationController, didStop options: [String: Any]?) { print("\\(#function) invoked with options: \\(options)") } }

Answer 1

You'd better work with [UIApplicationLaunchOptionsKey : Any] as it is.

How is this?

    if let launchOptions = launchOptions {
        for (kind, value) in launchOptions {
            appControllerContext.launchOptions[kind.rawValue] = value
        }
    }

---

UPDATED

Seems the type of the property launchOptions of TVApplicationControllerContext is [String: Any] , so you have no need to cast with as AnyObject .

Answer 2

try this code please and tell me what happen.

appControllerContext.launchOptions["BASEURL"] = AppDelegate.TVBaseURL

        if let launchOptions = launchOptions as? [String: Any] {
            for (kind, value) in launchOptions {
                appControllerContext.launchOptions[kind] = value
            }
        }