[英]How to create an instance from a DataTemplate
I have implemented a custom control that internally uses a ListView within the control template. 我实现了一个自定义控件,该控件在内部使用控件模板内的ListView。 This ListView is accessable by FindParts. 该ListView可通过FindParts访问。 I need to set the ListViews View property to an instance that I have to instanciate programmatically within my custom control. 我需要将ListViews View属性设置为必须在自定义控件中以编程方式实例化的实例。 I want to be able to create this instance from a DataTemplate that can be bound to a property of my custom control. 我希望能够从可以绑定到我的自定义控件的属性的DataTemplate创建此实例。
The problem is that I do not know how to create an instance from a DataTemplate. 问题是我不知道如何从DataTemplate创建实例。
Note that I do not want to bind a GridView directly to the View property (eg from a ResourceDictionary where the DataTemplates x:Shared attribute is set to false) as this leads to problems in the XAML designer (View can't be shared by more than one ListView). 请注意,我不想将GridView直接绑定到View属性(例如,从ResourceTemplatedictionary中,其中DataTemplates x:Shared属性设置为false),因为这会导致XAML设计器出现问题(视图不能由更多用户共享)多于一个ListView)。
Edit: Durig my discussion with grek40 it became clear that it is not possible to provide the GridView within a DataTemplate. 编辑: Durig与grek40的讨论非常清楚,不可能在DataTemplate中提供GridView。 Thus the answer marked as solution does not handle the question how to create an instance from a DataTemplate as implied by the title of my question. 因此,标记为解决方案的答案不能解决问题标题所暗示的问题,即如何从DataTemplate创建实例。
Since you didn't share much code, I made something out of thin air. 由于您没有共享太多代码,因此我凭空做出了一些事情。 The Idea: MyCustomControl
is hosting items and for that, a ListView
is used in the ControlTemplate
. 想法: MyCustomControl
托管项目,为此,在ControlTemplate
使用ListView
。 A default GridView
is included directly in the ControlTemplate
but it's possible to change it via MyCustomControl.MyView
默认的GridView
直接包含在ControlTemplate
但是可以通过MyCustomControl.MyView
进行更改
The Custom Control: 自定义控件:
public class MyCustomControl : ItemsControl
{
static MyCustomControl()
{
DefaultStyleKeyProperty.OverrideMetadata(typeof(MyCustomControl), new FrameworkPropertyMetadata(typeof(MyCustomControl)));
}
public ViewBase MyView
{
get { return (ViewBase)GetValue(MyViewProperty); }
set { SetValue(MyViewProperty, value); }
}
public static readonly DependencyProperty MyViewProperty =
DependencyProperty.Register("MyView", typeof(ViewBase), typeof(MyCustomControl), new FrameworkPropertyMetadata(null, new PropertyChangedCallback(OnMyViewChanged)));
private static void OnMyViewChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
((MyCustomControl)d).HasCustomView = e.NewValue != null;
}
// readonly property to support the Trigger in the ControlTemplate in order to exchange the ListView.View
public bool HasCustomView
{
get { return (bool)GetValue(HasCustomViewProperty); }
private set { SetValue(HasCustomViewPropertyKey, value); }
}
private static readonly DependencyPropertyKey HasCustomViewPropertyKey =
DependencyProperty.RegisterReadOnly("HasCustomView", typeof(bool), typeof(MyCustomControl), new PropertyMetadata(false));
public static readonly DependencyProperty HasCustomViewProperty = HasCustomViewPropertyKey.DependencyProperty;
}
The Control Template (note the default GridView and the Trigger for Replacement): 控制模板(请注意默认的GridView和替换触发器):
<Style TargetType="{x:Type local:MyCustomControl}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type local:MyCustomControl}">
<Border Background="{TemplateBinding Background}"
BorderBrush="{TemplateBinding BorderBrush}"
BorderThickness="{TemplateBinding BorderThickness}">
<ListView x:Name="PART_ListView"
ItemsSource="{Binding Items,RelativeSource={RelativeSource TemplatedParent}}">
<ListView.View>
<GridView>
<GridView.Columns>
<GridViewColumn Header="DEF"/>
</GridView.Columns>
</GridView>
</ListView.View>
</ListView>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="HasCustomView" Value="True">
<Setter TargetName="PART_ListView" Property="View" Value="{Binding MyView,RelativeSource={RelativeSource TemplatedParent}}"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
Usage: 用法:
<local:MyCustomControl>
<!--uses default view-->
<TextBlock Text="Item 1"/>
<TextBlock Text="Item 2"/>
</local:MyCustomControl>
<local:MyCustomControl>
<!--uses custom view-->
<local:MyCustomControl.MyView>
<GridView>
<GridView.Columns>
<GridViewColumn Header="ABC"/>
</GridView.Columns>
</GridView>
</local:MyCustomControl.MyView>
<TextBlock Text="Item 1"/>
<TextBlock Text="Item 2"/>
</local:MyCustomControl>
Feel free to ask if anything remains unclear. 随时询问是否还有不清楚的地方。 As commented, I don't know how to apply your DataTemplate
idea to all this stuff. 如前所述,我不知道如何将您的DataTemplate
想法应用于所有这些内容。
Edit: 编辑:
The following is a an example with resource section to define some data and DataTemplate
s as well as their possible usage. 以下是带有资源部分的示例,用于定义一些数据和DataTemplate
以及它们的可能用法。
<StackPanel>
<StackPanel.Resources>
<x:Array x:Key="Items1" Type="{x:Type sys:Int32}">
<sys:Int32>1</sys:Int32>
<sys:Int32>2</sys:Int32>
<sys:Int32>3</sys:Int32>
<sys:Int32>4</sys:Int32>
</x:Array>
<x:Array x:Key="Items2" Type="{x:Type sys:Int32}">
<sys:Int32>5</sys:Int32>
<sys:Int32>4</sys:Int32>
<sys:Int32>6</sys:Int32>
<sys:Int32>7</sys:Int32>
</x:Array>
<CollectionViewSource x:Key="ItemsSource1" Source="{StaticResource Items1}"/>
<CollectionViewSource x:Key="ItemsSource2" Source="{StaticResource Items2}"/>
<DataTemplate x:Key="IntegerListTemplate1">
<local:MyCustomControl ItemsSource="{Binding}">
<!--uses default view-->
</local:MyCustomControl>
</DataTemplate>
<DataTemplate x:Key="IntegerListTemplate2">
<local:MyCustomControl ItemsSource="{Binding}">
<!--uses custom view-->
<local:MyCustomControl.MyView>
<GridView>
<GridView.Columns>
<GridViewColumn Header="ABC"/>
</GridView.Columns>
</GridView>
</local:MyCustomControl.MyView>
</local:MyCustomControl>
</DataTemplate>
</StackPanel.Resources>
<!--the default view-->
<ContentControl ContentTemplate="{StaticResource IntegerListTemplate1}" Content="{Binding Source={StaticResource ItemsSource1}}"/>
<Separator Margin="3"/>
<!--same items other view-->
<ContentControl ContentTemplate="{StaticResource IntegerListTemplate2}" Content="{Binding Source={StaticResource ItemsSource1}}"/>
<Separator Margin="3"/>
<!--different items same view as second one, no complaints about reusing-->
<ContentControl ContentTemplate="{StaticResource IntegerListTemplate2}" Content="{Binding Source={StaticResource ItemsSource2}}"/>
</StackPanel>
Edit 2, targeting the commented MCVE: 编辑2,针对评论的MCVE:
I would solve this exactly as I already explained in my first edit. 我将按照我在第一次编辑中已经解释的完全解决这个问题。 Turn your control into a DataTemplate
, not the view into a style. 将控件变成DataTemplate
,而不是将视图变成样式。
Replace in MainWindow.xaml: 在MainWindow.xaml中替换:
<!-- old -->
<myctrls:MyControl Grid.Row="0" Grid.Column="0" Style="{StaticResource AddressStyle}" ItemsSource="{Binding Addresses}"/>
<!-- new -->
<ContentControl Grid.Row="0" Grid.Column="0" ContentTemplate="{StaticResource AddressTemplate}" Content="{Binding Addresses}"/>
Same with the other occurences. 与其他事件相同。
In MyControlStyles.xaml (or a renamed file that indicates DataTemplate
usage), merge the GridView
resource and the Style
with the myctrls:MyControl
into a DataTemplate
. 在MyControlStyles.xaml(或指示DataTemplate
使用的重命名文件)中,将GridView
资源和Style
与myctrls:MyControl
合并到DataTemplate
。
Old: 旧:
<GridView x:Key="AddressGridView" x:Shared="False">
<GridViewColumn Header="City" Width="Auto" >
<GridViewColumn.CellTemplate>
<DataTemplate>
<TextBlock Text="{Binding City}" HorizontalAlignment="Left"/>
</DataTemplate>
</GridViewColumn.CellTemplate>
</GridViewColumn>
<GridViewColumn Header="Country" Width="Auto" >
<GridViewColumn.CellTemplate>
<DataTemplate>
<TextBlock Text="{Binding Country}" HorizontalAlignment="Left"/>
</DataTemplate>
</GridViewColumn.CellTemplate>
</GridViewColumn>
</GridView>
<Style x:Key="AddressStyle" TargetType="{x:Type myctrls:MyControl}">
<Setter Property="SuggestionsView" Value="{DynamicResource AddressGridView}"/>
</Style>
New: 新:
<DataTemplate x:Key="AddressTemplate">
<!-- the base control -->
<myctrls:MyControl ItemsSource="{Binding}">
<!-- this was previously assigned by AddressStyle -->
<myctrls:MyControl.SuggestionsView>
<!-- this was previously the AddressGridView -->
<!-- Same as before, only removed the x:Key and x:Shared -->
<GridView>
<GridViewColumn Header="City" Width="Auto" >
<GridViewColumn.CellTemplate>
<DataTemplate>
<TextBlock Text="{Binding City}" HorizontalAlignment="Left"/>
</DataTemplate>
</GridViewColumn.CellTemplate>
</GridViewColumn>
<GridViewColumn Header="Country" Width="Auto" >
<GridViewColumn.CellTemplate>
<DataTemplate>
<TextBlock Text="{Binding Country}" HorizontalAlignment="Left"/>
</DataTemplate>
</GridViewColumn.CellTemplate>
</GridViewColumn>
</GridView>
</myctrls:MyControl.SuggestionsView>
</myctrls:MyControl>
</DataTemplate>
Same procedure for the ProductsStyle
. 与ProductsStyle
相同的过程。
If you don't like the ContentControl
wire-up approach, consider the creation of additional viewmodels that host then collections, like AddressListViewModel
. 如果您不喜欢ContentControl
的连接方法,请考虑创建用于承载集合的其他视图模型,例如AddressListViewModel
。 This would allow you to handle the DataTemplate
by DataType
instead of resource key and explicit usage in ContentControl
. 这将允许您通过DataType
处理DataTemplate
,而不是ContentControl
的资源键和显式用法。
You could implement your own DataTemplateSelector, which then dynamically creates your one-time-use DataTemplate, roughly like that: 您可以实现自己的DataTemplateSelector,然后动态创建您的一次性DataTemplate,大致如下所示:
public DataTemplate GenerateTemplate() {
var template = new DataTemplate();
var p = new FrameworkElementFactory(typeof(Grid));
p.SetValue(FrameworkElement.HorizontalAlignmentProperty, HorizontalAlignment.Left);
p.SetValue(FrameworkElement.VerticalAlignmentProperty, VerticalAlignment.Center);
...
template.VisualTree = p;
return template;
}
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