ajax调用时jquery typeahead插件不起作用

Question

I search all questions about typeahead plugin in this forum and have tried all the ways i can. But i have a problem yet. Im using codeigniter and want to autocomplete by typeahead plugin via ajax. This is my js code:

$('.typeahead').typeahead({
    hint: true,
    highlight: true,
    minLength: 1
}, {
    source: function (query, process) {
        $.ajax({
            url: baseUrl + 'panel/yazilarim/deneme',
            type: 'POST',
            data: 'query=' + query,
            dataType: 'JSON',
            async: true,
            success: function (data) {
                console.log(data);
                process(data);
            }
        });
    }
});

public function deneme() {
    $aranan = $this->input->post("query");
    $sorgu = $this->db->select("ad")->from("kategori")->where("ad LIKE '%" . $aranan . "%' ")->get();

    $sonuclar = $sorgu->result_array();
    $dizi = [];
    foreach ($sonuclar as $sonuc) {
        $dizi[] = $sonuc["ad"];
    }
    echo json_encode($dizi);
}

console.log() function works well, i can see the result array, but the dropdown menu never appears. I've load bundle and typeahead js files and the css file. Any suggestions?

Answer 1

This is how i implemented typeahead in my CodeIgniter project. Please refer the my working code. In the view page

    <script src="<?php echo base_url('assets/js/typeahead.min.js'); ?>" > </script>
     <script>
    $(document).ready(function(){
    $('input.typeahead').typeahead({
        name: 'typeahead',
        remote:'<?php echo base_url(); ?>panel/yazilarim/deneme?query=%QUERY',
        limit : 5
    });
});
 </script>



<div class="form-group">
      <input type="text" name="member"  class="form-control typeahead" style="width:280px;"  autocomplete="off" >
</div>

In the controller

public function deneme() {
    $aranan = $this->input->get("query");
    $sorgu = $this->db->select("ad")->from("kategori")->where("ad LIKE '%" . $aranan . "%' ")->get();

    $sonuclar = $sorgu->result_array();
    $dizi = [];
    foreach ($sonuclar as $sonuc) {
        $dizi[] = $sonuc["ad"];
    }
    echo json_encode($dizi);
}

I think your controller is right. If it doesn't work please comment the problem below.Remember i use get method.

Answer 2

You forgot to return result. Please try this:

success: function (data) {
    console.log(data);
    return process(data);
}

Also, set async:false property.

At a very basic level, you use an asynchronous mode when you want the call to occur in the background and a synchronous mode when you want your code to wait until the call has completed.

Here is asyncronous version.

source: function (query, process) {
   var getData = getData();
   getData.done(function(data){
      return process(data);
    // do stuff with `information` here, not elsewhere.
   });
   function getData(){ 
      return $.ajax({
        url: baseUrl + 'panel/yazilarim/deneme',
        type: 'POST',
        data: 'query=' + query,
        dataType: 'JSON'
      });
   }
}