如果count> 0，如何检查连续计数并返回布尔值

Question

I'm using Nodejs and I have a query to get count. I want to check if count > 0 to return true, else - false. But I can't handle it using nodejs. Here's my code:

 const uidIsConnection = (model, entityId, uid) => models[model].count({ where: { entityId, profileId: uid } }); var data = uidIsConnection('ProfileData', user.id, id); //I want this variable data to have the value of true or false 

Now, data returns promise:

 Promise { _bitField: 2097152, _fulfillmentHandler0: undefined, _rejectionHandler0: undefined, _promise0: undefined, _receiver0: undefined, _boundTo: profiledata } 

How to return boolean value depending on count > 0 , not promise?

Answer 1

Sequelize count returns a Promise, which is what your data is resolving to. To get the actual count of the function you should do:

const uidIsConnection = (model, entityId, uid) =>
        models[model].count({
            where: { entityId, profileId: uid }
        });

uidIsConnection('ProfileData', user.id, id).then(count => {
    console.log('boolean version of count', !!count);
});

In the future you could use asyc await to resolve this synchronously, but the feature is not widely supported yet .