PHP计数更改日期格式的mysql行

Question

I have next problem: My table date format was: LIKE 2017-01-08 18:50:25 (with time).

When i use sql query like

'SELECT date FROM table WHERE date = "2017-01-08"'

My row was empty, i need COUNT all row with same (today) date WITHOUT TIME.

Note, i will not change INSERT date time!

Answer 1

Use DATE() to get the date portion of the datetime field and compare it to today. Use COUNT() to get the number of records that match your query.

SELECT count(*) FROM table WHERE DATE(date) = CURDATE()

You can also replace CURDATE() with NOW() , CURRENT_DATE() , and CURRENT_DATE

Answer 2

You can also use it in the following way

'SELECT date FROM table WHERE date_format(date,'%Y-%m-%d') = "2017-01-08"'

the date_format is mysql function which return date according to your pattern the above pattern only return the Ymd from the datetime I hope it will help you

Answer 3

plz change your statement equal operator to greater than

'SELECT date FROM table WHERE date > "2017-01-08"'

as by default if time portion is not present then it is putting 00:00...