获取项目LongClicked在ListView中的位置

Question

I have a ListView displaying custom views (3 TextViews per item); I have just implemented a context menu like such:

// in onCreateView
ListView list = (ListView) view.findViewById(R.id.list);

registerForContextMenu(list);

and

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);

    if (v.getId() == R.id.list) {
        MenuInflater inflater = getActivity().getMenuInflater();
        inflater.inflate(R.menu.todo_context_menu, menu);
    }
}

@Override
public boolean onContextItemSelected(MenuItem item) {
    switch (item.getItemId()) {
        case R.id.edit:
            // your first action code
            return true;
        case R.id.delete:
            // your second action code
            return true;
        default:
            return super.onContextItemSelected(item);
    }
}

I wish to know which item has been long clicked (its position in the ListView would be ideal) in order to edit or delete the right one.

How may that be achieved?

Answer 1

@Override
public boolean onContextItemSelected(MenuItem item) {

   AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
   int index = info.position;

  switch (item.getItemId()) {
    case R.id.edit:
        // your first action code
        return true;
    case R.id.delete:
        // your second action code
        return true;
    default:
        return super.onContextItemSelected(item);
  }
}