无线电检查不起作用？

Question

I am just check if the radio checked button checked or not but it's not show alert.

My code is here:

js code:

var dayshift=document.getElementsByName("dayshift");
var weekshift=document.getElementsByName("weekshift");

if(dayshift.checked && weekshift.checked)
{
  alert("shift");
}

My html code:

html code:

<input type="radio" name="dayshift" value="Day" checked/> 
<input type="radio" name="dayshift" value="Night"/> 
<input type="radio"  name="weekshift" value="Weekday" checked/> 
<input type="radio"  name="weekshift" value="Weekend" /> 

Answer 1

Since getElementsByName returns array. you can access your element by indexing dayshift[0] for first element

 var dayshift = document.getElementsByName("dayshift"); var weekshift = document.getElementsByName("weekshift"); if (dayshift[0].checked && weekshift[0].checked) { console.log("shift"); }

 <input type="radio" name="dayshift" value="Day" checked/> <input type="radio" name="dayshift" value="Night" /> <input type="radio" name="weekshift" value="Weekday" checked/> <input type="radio" name="weekshift" value="Weekend" />

Answer 2

Try with this

$("input[name=dayshift]").prop("checked", true);

so if you do in condition

if($("input[name=dayshift]").prop("checked", true)){
     alert("checked/shifted");
}