[英]Exporting default value from a module in Typescript declaration file
Let's say I have a declarations file foo.d.ts
: 假设我有一个声明文件
foo.d.ts
:
declare namespace foo {
interface Bar {
(): void;
}
}
declare var foo: foo.Bar;
export default foo;
If I compile this: 如果我编译此:
import Foo from './foo';
Foo();
The resulting output is: 结果输出为:
"use strict";
var foo_1 = require('./foo');
foo_1["default"]();
However this code won't run as foo_1
is a function and has no property default
. 但是,由于
foo_1
是一个函数且没有default
属性,因此该代码无法运行。 How can I get the output to be foo_1()
instead of foo_1["default"]()
? 如何获取输出为
foo_1()
而不是foo_1["default"]()
?
Use 采用
export = foo;
instead of export default foo;
而不是
export default foo;
in your declaration file 在您的申报文件中
and use import require
when importing: 并在导入时使用
import require
:
import Foo = require('./foo');
Export assignment/import require is special syntax in typescript for dealing with node modules with exports like 导出分配/导入要求是打字稿中的特殊语法,用于处理带有导出之类的节点模块
module.exports = function someFunction() {}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.