我的函数出于某种原因会自动将字符串转换为元组？

Question

I'm very confused here. I'm trying to pass an optional string parameter to my function, but once the parameter is added, it converts the string to a tuple? How can I stop it from doing that or convert back?

I have this:

def fen2grid(note, *optional)
    print(optional)
    # here it does other stuff

With this when I call it:

fen2grid(example, '.')

now... the print is supposed to print a period. Just . This is just a test before I use it in the function and it seems to be a good thing that I'm testing it.What it prints is

('.',)

I need the period because I need to work with that (it can be any other symbol too)

Any help would be appreciated!

Answer 1

*args reads an arbitrary number of arguments and encloses them as a tuple. To access them you can simply do print(args[0]) or [print(x) for x in args]

Edit: Keep in mind that neither args or kwargs are keywords, you can replace them for any other placeholder preceded by * or **

Answer 2

I'm trying to pass an optional string parameter to my function

*optional isn't quite how you do that. At least not for default/keyword argument like you are trying to use. That is a tuple .

Try

def fen2grid(note, optional=None)
    print(optional)

For more details, see about Defining Functions .