如果数字长度为5位或更长，则在python中断开字符串

Question

I know I can break a string in python using:

s = re.split("[0-9]|  ", string)[0].strip()

However, I would like to break the string only if I have 5 or more consecutive digits.

Ex.

Hello1234 => Hello1234
Hello12345 => Hello

How can I achieve this?

Answer 1

就像是

s = re.split("[0-9]{5,}", string)[0].strip()

Answer 2

Alternatively you can also use re.sub to remove everything after 5 digits:

>>> re.sub('[0-9]{5,}.*', '', 'Hello12345World')
'Hello'

>>> re.sub('[0-9]{5,}.*', '', 'Hello12345')
'Hello'

>>> re.sub('[0-9]{5,}.*', '', 'Hello1234')
'Hello1234'

Answer 3

(\\D)*(?=\\d{5,})

matches any string with 5 digits+

the first capture group will match your string without the digits

http://regexr.com/ will allow you to test regular expressions, and also has a reference guide