如何仅推送数组中未找到的元素

Question

So the question is asking me to remove punctuation from my word and i know how to cross-reference the tho arrays to check if an element exists in my array to be checked but how do i only push the values that are not in my punctuation array?

function removePunctuation(word){
  var punctuation = [";", "!", ".", "?", ",", "-"];
  var chars = word.split("");
  var puncRemoved = [];
  for(var i = 0; i < chars.length;i++){
    for(var j = 0; j < punctuation.length;j++) {
      if(punctuation[j].indexOf(chars[i]) !== 0) {
        puncRemoved.push(i)
      }
    }
  }
  return puncRemoved;
}

Answer 1

word.replace(/[;\!\.\?\,-]/g, '');

您可能会发现这很有趣：D

Answer 2

Here's a solution which is based on your code:

function removePunctuation(word){
  var punctuation = [";", "!", ".", "?", ",", "-"];
  var chars = word.split("");
  var puncRemoved = [];
  for (var i = 0; i < chars.length; i++) {

    // Push only chars which are not in punctuation array
    if (punctuation.indexOf(chars[i]) === -1) {
        puncRemoved.push(chars[i]);
    }
  }

  // Return string instead of array
  return puncRemoved.join('');
}

Another way to implement this would be:

function removePunctuation(word){
  var punctuation = [";", "!", ".", "?", ",", "-"];

  // Iterate and remove punctuations from the given string using split().join() method
  punctuation.forEach(function (p) {
    word = word.split(p).join('');
  });

  return word;
}

Or, as suggested in another answer:

function removePunctuation(word){
    return word.replace(/[;\!\.\?\,-]/g, '');
}

Answer 3

You need to push the value when it's not found in the array, so:

punctuation.indexOf(chars[i]) == -1

but a regular expression seems so much simpler.

Edit

To make it clear, you need to iterate over the characters and only push them if they don't appear in the punctuation array:

 function removePunctuation(word){ var punctuation = [";", "!", ".", "?", ",", "-"]; var chars = word.split(""); var puncRemoved = []; for(var i = 0; i < chars.length;i++){ if(punctuation.indexOf(chars[i]) == -1) { puncRemoved.push(chars[i]) } } return puncRemoved; } var s = 'Hi! there. Are? you; ha-ppy?'; console.log(removePunctuation(s).join(''))