使用管道时重组bash参数

Question

What approach can be used in case of recombine bash arguments, for example: 在重组bash参数的情况下可以使用什么方法，例如：

echo "arg3 arg1 arg2" | ...

so as recombine arguments in random sort can be applicable: 因此可以采用随机排序的重组参数：

... | some_command -arg1=$3 -arg2=$1 -arg3=$2 --interpretator-arg=$0 --anoter-arg=$1$2$3

Answer 1

One option would be to use read : 一种选择是使用read ：

echo "arg3 arg1 arg2" | { read -r a b c; some_command ...; }

Now you can use arguments "$a" , "$b" and "$c" as you wish. 现在，您可以根据需要使用参数"$a" ， "$b"和"$c" 。

I guess your example is a bit artificial but you can avoid a pipeline in this case: 我想您的示例有点人为，但在这种情况下可以避免使用管道：

{ read -r a b c; some_command ...; } <<< "arg3 arg1 arg2"

If the arguments really come from a command, then you can use a command substitution: 如果参数确实来自命令，则可以使用命令替换：

{ read -r a b c; some_command ...; } < <(command_producing_arguments)

Note that the semicolon at the end is important, if the command group { } is written all on one line. 请注意，如果命令组{ }全部写在一行上，则末尾的分号很重要。