Bash-查找并替换目录中文件中的一行

Question

I have a file structure where I have 700 directories. All the directories have a file named config.xml . I have prefixed 25 directories with 1111- name. Now, I want to replace a block of code in config.xml files from all those 25 directories. I want to have a loop ( for or while ) for that.

Answer 1

您可以使用find搜索文件， grep目录并使用sed替换字符串。

find . -iname 'config.xml' | grep '1111' | sed -i 's/STRINGTOREPLACE/NEWSTRING/'

Answer 2

尝试这个：

find . -name "1111-*" -type d -exec cd {} \; -exec /absolute.path/to/shell_script_modifying_config.xml \;

Answer 3

I would use a recursive function:

folder_recursive() {
    for i in "$1"/*;do
        if [ -d "$i" ];then
            folder_recursive "$i"
        elif [ -f "$i" ]; then
            lastFolder = ${$1##*/}
            if [[ $lastFolder == *"1111-"* ]]; then
                if [[ $i == *"config.xml" ]]; then
                    #Replace block of code
                    file_path=$i
                    original=$(<file_path) # Read from file
                    to_replace="aaaabbbb"
                    replacer="xxxxyyyy"
                    result=${original/$to_replace/$replacer} #This will replace the first instance of to_replace
                    # If you want to replace all instances use:
                    # ${original//$to_replace/$replacer}
                    echo $result > $i #Overwrite file
                fi
            fi
        fi
    done
}

path= "root/of/folder/structure"
folder_recursive $path