从哈希内递归访问数组中的最后一个值

Question

The input may come something from string or array within hash .

However,

• Hash could be recursive.
• Array could have multiple values.

Example;

  # ex.1  "name must be a string"
  # ex.2 {"name"=>["name must be a string"]}
  # ex.3  {"name"=>["name must be a string", "name must be greater than 3"]}
  # ex.4 {"payment"=> {"currency"=>["currency must be a jpy"]}}
  # ex.5 {"payment"=> {"currency"=>["currency must be a jpy", "currency must be string"]}}

I'd love to render the string or each of the last values within array.

  # ex.1 method(x) => "name must be a string"
  # ex.2 method(x) => "name must be a string"
  # ex.3 method(x) => "name must be a string"/ "name must be greater than 3"
  # ex.4 method(x) => "currency must be a jpy"
  # ex.5 method(x) => "currency must be a jpy"/ "currency must be string"

Answer 1

def leaves(input, acc = [])
  if input.is_a?(Enumerable)
    input.each_with_object(acc) { |e, acc| leaves([*e].last, acc) }
  else
    acc << input
  end
end 

leaves({ 1=>{2=>[3,4], 3=>[5,[6, 7]] }})
#⇒ [3, 4, 5, 7]

Answer 2

def last_values(val)
  vals = if val.is_a?(Hash)
           val = val[val.keys.last]
           return val.values.flatten if val.is_a?(Hash) # for Hash fetch the last one
           return val.flatten # for Array
         else
           [val]
         end

  vals.each do |each|
     p each
  end
end

This could work. However if you have any other good solutions, please post it up :)