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替换包含特殊字符的完全匹配词

[英]Replace exact matching words containing special characters

I came across How to search and replace exact matching strings only . 我遇到了如何仅搜索和替换完全匹配的字符串 However, it doesn't work when there are words that start with @. 但是,当有以@开头的单词时,它不起作用。 My fiddle here https://dotnetfiddle.net/9kgW4h 我的小提琴在这里https://dotnetfiddle.net/9kgW4h

string textToFind = string.Format(@"\b{0}\b", "@bob");
Console.WriteLine(Regex.Replace("@bob!", textToFind, "me"));// "@bob!" instead of "me!"

Also, in addition to that what I would like to do is that, if a word starts with \\@ say for example \\@myname and if I try to find and replace @myname, it shouldn't do the replace. 另外,除了我想做的以外,如果一个单词以\\ @开头,例如说\\ @myname,并且如果我尝试查找并替换@myname,则不应执行替换。

I suggest replacing the leading and trailing word boundaries with unambiguous lookaround-based boundaries that will require whitespace chars or start/end of string on both ends of the search word, (?<!\\S) and (?!\\S) . 我建议用明确的基于环顾四周的边界替换开头和结尾的词边界,这将需要在搜索词(?<!\\S)(?!\\S)两端使用空格字符或字符串的开头/结尾。 Besides, you need to use $$ in the replacement pattern to replace with a literal $ . 此外,您需要在替换模式中使用$$来替换文字$

I suggest: 我建议:

using System;
using System.Text.RegularExpressions;

public class Program
{
    public static void Main()
    {
        string text = @"It is @google.com or @google w@google \@google \\@google";
        string result = SafeReplace(text,"@google", "some domain", true);
        Console.WriteLine(result);
    }


    public static string SafeReplace(string input, string find, string replace, bool matchWholeWord)
    {
        string textToFind = matchWholeWord ? string.Format(@"(?<!\S){0}(?!\S)", Regex.Escape(find)) : find;
        return Regex.Replace(input, textToFind, replace.Replace("$","$$"));
    }
}

See the C# demo . 参见C#演示

The Regex.Escape(find) is only necessary if you expect special regex metacharacters in the find variable value. 仅当您希望find变量值中包含特殊的正则表达式元字符时,才需要Regex.Escape(find)

The regex demo is available at regexstorm.net . regex演示可从regexstorm.net获得

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