如何从数组中删除所有不包含包含特定字符串的字段的元素？

Question

This is some of the result obtained from an ElasticSearch query ..

"buckets": [{
    "key": "another_service_name:0.0.1",
    "doc_count": 105,
    "containers": {
        "doc_count_error_upper_bound": 0,
        "sum_other_doc_count": 0,
        "buckets": [{
            "key": "7eaf4933b0366f7212f30f9f3c315672ea18e026922d0651b29b844763be6b0a",
            "doc_count": 105,
            "someField": {
                "value": 1.2708647376015072
            }
        }]
    }
}, {
    "key": "my_service_name:0.0.1",
    "doc_count": 200,
    "containers": {
        "doc_count_error_upper_bound": 0,
        "sum_other_doc_count": 0,
        "buckets": [{
            "key": "4c27931147386d49e90f581a1d5cb22f53cda00b16107864cad9eff32f61d776",
            "doc_count": 100,
            "someField": {
                "value": 77.9621390914917
            }
        }, {
            "key": "392e7e6981cd4c24c526ffda03977b7984ebcae58194680c82940af4acec4748",
            "doc_count": 100,
            "someField": {
                "value": 76.63604362487793
            }
        }]
    }
}]

Is there a simple 1-liner to remove any elements from the outter buckets array that do not have the key containing my_service_name ?

I know I could loop over the array, use indexOf and splice .. but is there a shorter way?

I would like the result to look like this ..

"buckets": [{
    "key": "my_service_name:0.0.1",
    "doc_count": 200,
    "containers": {
        "doc_count_error_upper_bound": 0,
        "sum_other_doc_count": 0,
        "buckets": [{
            "key": "4c27931147386d49e90f581a1d5cb22f53cda00b16107864cad9eff32f61d776",
            "doc_count": 100,
            "someField": {
                "value": 77.9621390914917
            }
        }, {
            "key": "392e7e6981cd4c24c526ffda03977b7984ebcae58194680c82940af4acec4748",
            "doc_count": 100,
            "someField": {
                "value": 76.63604362487793
            }
        }]
    }
}]

Answer 1

You could use the Array.prototype.filter method:

var queryResults = /* your result as above */;

var myServices = queryResults.filter(function(element) {
    return element.key.indexOf('my_service_name') >= 0;
})

In ES6 it's possible to shorten this to:

let queryResults = /* your result as above */;

let myServices = queryResults.filter(element => element.key.includes('my_service_name'))

Answer 2

A one-liner can be the Array.filter method, like this:

buckets.filter( item => /my_service_name:/i.test(item.key) );

As lonesomeday mentions, the arrow function is not working in Internet Explorer (and filter might not be working to), to still use this almost one liner, you could rewrite it as:

buckets.filter( function(item) { return /my_service_name:/i.test( item.key ); } );

To support filter in Internet Explorer, you can use the polyfill supplied on the MDN page

 var buckets = [{ "key": "another_service_name:0.0.1", "doc_count": 105, "containers": { "doc_count_error_upper_bound": 0, "sum_other_doc_count": 0, "buckets": [{ "key": "7eaf4933b0366f7212f30f9f3c315672ea18e026922d0651b29b844763be6b0a", "doc_count": 105, "someField": { "value": 1.2708647376015072 } }] } }, { "key": "my_service_name:0.0.1", "doc_count": 200, "containers": { "doc_count_error_upper_bound": 0, "sum_other_doc_count": 0, "buckets": [{ "key": "4c27931147386d49e90f581a1d5cb22f53cda00b16107864cad9eff32f61d776", "doc_count": 100, "someField": { "value": 77.9621390914917 } }, { "key": "392e7e6981cd4c24c526ffda03977b7984ebcae58194680c82940af4acec4748", "doc_count": 100, "someField": { "value": 76.63604362487793 } }] } }]; console.log( buckets.filter( item => /my_service_name:/i.test(item.key) ) );