[英]IF and ELSE Statement based on column value
Based on one column within my query results (Value), I am trying to write an if/else statement based on the value held which will display the result the in an additional row.基于我的查询结果(值)中的一列,我试图根据所持有的值编写一个 if/else 语句,该语句将在另一行中显示结果。
For example, if I have a record of 2 within the value field, but I want to check whether it is above < 5. If the value is less than 5 I basically want the additional column to display a hardcoded value of 5, else display actual value.例如,如果我在 value 字段中有 2 的记录,但我想检查它是否在 < 5 以上。如果值小于 5 我基本上希望附加列显示硬编码值 5,否则显示实际价值。
Any help would be appreciated.任何帮助,将不胜感激。
Use a case
statement使用
case
语句
select a.*,
case
when a.TheField < 5 then 5
else a.TheField
end as NewField
from MyTable a
You can use a case
你可以使用一个
case
select value, case when value < 5
then 5
else value
end as calculated_column
from your_table
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