获取选择字符串输出的子字符串的最佳方法是什么？

Question

I am running Select-String on a file which contains the following line:

....
Association ID: uj8da-21
....

Select-String -Path "..path.." -Pattern "Association ID:" -SimpleMatch gives me the file, the line number, the words "Association ID:", etc. All I want is the value. What's the best way to do this from the Select-String command?

And what if I wanted to extract a series of lines after this line (say, 10 additional lines) -- would the -Context argument be the way to go?

Answer 1

Use match groups.

$matchInfo = Select-String -Path "C:\temp\text.txt" -Pattern "Association ID: (.*)" 
$matchInfo.Matches.Groups[1].Value

Context is the way to go.

$matchInfo = Select-String -Path "C:\temp\text.txt" -Pattern "Association ID: (.*)" -Context 0,10
$matchInfo.Matches.Groups[1].Value
$matchInfo.Context.PostContext