如果xpath中的条件为真，如何获取元素

Question

I have an XML file like this:

<div class="main">
    <div aria="location">
        ...
    </div>
    <div class="transcript">
        ...
    </div>
</div>

I want to get the div with aria=" location " if there is an element and if there is not an element with that condition get the div with class=" transcript " . I check my XPath in the chrome inspect element tab and I want to work with that.

Answer 1

You could use XPath:

(//div[@aria='location']|//div[@class='transcript' and not(following::div[@aria='location'])])[1]

Explanation:

• ( grouping
  • //div[@aria='location'] find a div element with an aria attribute value location
  • | or
  • //div[@class='transcript' and not(following::div[@aria='location'])] find a div element with a class attribute value transcript and there is no div element with an aria attribute value location after it, in document order
• ) end grouping
• [1] take the first result

the following check is necessary, because if we just used:

(//div[@aria='location']|//div[@class='transcript])[1]

then, if the div element with class transcript came before the div with aria location in document order, then the div with class transcript would be returned due to how XPath traversal works.