动态PHP功能

Question

How can we declare the function name dynamically?

For example :

$function = 'test'
public $function(){

}

Answer 1

You could use a callback for this:

https://stackoverflow.com/a/2523807/3887342

function doIt($callback) { $callback(); }

doIt(function() {
    // this will be done
});

Answer 2

Declaring a function with a variable but arbitrary name like this is not possible without getting your hands dirty with eval() or include().

I think based on what you're trying to do, you'll want to store an anonymous function in that variable instead (use create_function() if you're not on PHP 5.3+):

$variableA = function() {
    // Do stuff
};

You can still call it as you would any variable function , like so:

$variableA();