如何使用Saxon s9api进行XSLT 2.0转换？ XML文件到XML文件

Question

I'm new to XML so bear with me. I need to transform an xml file to another xml file. It needs xslt 2.0. I am using saxon's s9api. Using their documentation this what I have so far:

import java.io.File;
import javax.xml.transform.stream.StreamSource;
import net.sf.saxon.s9api.DocumentBuilder;
import net.sf.saxon.s9api.Processor;
import net.sf.saxon.s9api.SaxonApiException;
import net.sf.saxon.s9api.XsltCompiler;
import net.sf.saxon.s9api.XsltExecutable;
import net.sf.saxon.s9api.XsltTransformer;



class Main{
    public static void main(String args[]){

        Processor processor = new Processor(false);
        XsltCompiler compiler = processor.newXsltCompiler();
        DocumentBuilder builder = processor.newDocumentBuilder();
        try {
            builder.build(new File("C:\\XMLFILE.xml"));
        } catch (SaxonApiException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
        try {
            XsltExecutable xsl = compiler.compile(new StreamSource(new File("C:\\XSLFILE.xsl")));
            XsltTransformer trans = xsl.load();
            trans.transform();


        } catch (SaxonApiException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }
}

Is this the right direction? If it is and this is actually performing the transformation how do I specify the output xml.

Answer 1

You can set a destination on the transformer, for example an output File.

Serializer out = new Serializer();
out.setOutputProperty(Serializer.Property.METHOD, "html");
out.setOutputProperty(Serializer.Property.INDENT, "yes");
out.setOutputFile(new File("<filelocation>"));

Then set on the transformer

transformer.setDestination(out);

Before you make the call to transform().

trans.transform();