这两种在JavaScript函数中利用arguments对象的方式有什么区别？

Question

In the documentation for the Array.prototype.slice method it says:

Binding can be done with the .call function of Function.prototype and it can also be reduced using [].slice.call(arguments) instead of Array.prototype.slice.call.

function getArgs() {
  var args = [].slice.call(arguments);
  return args;
}
getArgs(1,2,3); // returns [1, 2, 3]

function getArgs2() {
  var args = Array.prototype.slice.call(arguments);
  return args;
}
getArgs2(1,2,3); // returns [1, 2, 3]

Essentially what is the difference? Is there a performance benefit using one over the other method? Or is the former just easier to type out?

Answer 1

Those both do the same thing, which is to call the array .slice() method. The first way gets at the function via the implicit prototype lookup from a new empty array, and the other goes explicitly to the Array.prototype object. There is probably a performance difference but it's not significant or relevant, since both ways throw away a lot of performance anyway: passing the arguments object out of a function is likely to make the runtime system give up on optimizing the function.

To avoid that performance penalty, a simple local for loop should be used instead:

function foo() {
  var args = [];
  for (var i = 0; i < arguments.length; ++i) args[i] = arguments[i];
  // ...
}