在col 1中查找字符串，在awk中打​​印col 2

Question

I'm on a Mac, and I want to find a field in a CSV file adjacent to a search string

This is going to be a single file with a hard path; here's a sample of it:

84:a5:7e:6c:a6:b0, AP-ATC-151g84
84:a5:7e:6c:a6:b1, AP-A88-131g84
84:a5:7e:73:10:32, AP-AG7-133g56
84:a5:7e:73:10:30, AP-ADC-152g81
84:a5:7e:73:10:31, AP-D78-152e80

so if my search string is "84:a5:7e:73:10:32" I want to get returned "AP-AG7-133g56"

I had been working within an Applescript, but maybe a shell script will do.

I just need the proper syntax for opening the file and having awk search it. Again, I'm weak conceptually on how shell commands run, how they must be executed, etc

This errors, gives me ("command not found"):

set the_file to "/Users/Paw/Desktop/AP-Decoder 3.app/Contents/Resources/BSSIDtable.csv"
set the_val to "70:56:81:cb:a2:dc"
do shell script "'awk $1 ~ the_val {print $2} the_file'"

Thank you for coddling me...

Answer 1

This is a relatively simple:

awk '$1 == "70:56:81:cb:a2:dc," {print "The answer is "$2}' 'BSSIDtable.csv'

(the "The answer is " text can be omitted if you only wish to see only the data, but this shows you how to get more user-friendly output if desired).

The comma is included since awk uses white space for separators so the comma becomes part of column 1.

If the thing you're looking for is in a shell variable, you can use -v to provide that to awk as an awk variable:

lookfor="70:56:81:cb:a2:dc,"
awk -v mac=$lookfor '$1 == mac {print "The answer is "$2}' 'BSSIDtable.csv'

As an aside, your AppleScript solution is probably not working because the $1/$2 are being interpreted as shell variable rather than awk variables. If you insist on using AppleScript, you will have to figure out how to construct a shell command that quotes the awk commands correctly.

My advice is to just use the shell directly, the number of people proficient in that almost certainly far outnumber those proficient in AppleScript :-)

Answer 2

if sed is available (normaly on mac, event if not tagged in OP)

simple but read all the file

sed -n 's/84:a5:7e:73:10:32,[[:blank:]]*//p' YourFile

quit after first occurence (so average of 50% faster on huge file)

sed -n -e '/84:a5:7e:73:10:32,[[:blank:]]*/!b' -e 's///p;q' YourFile

awk

awk '/^84:a5:7e:73:10:32/ {print $2}'
# OR using a variable for batch interaction
awk -v Src='84:a5:7e:73:10:32' '$1 == Src {print $2}'
# OR assuming that case is unknow
awk -v Src='84:a5:7e:73:10:32' 'BEGIN{IGNORECASE=1} $1 == Src {print $2}'

by default it take $0 as compare test if a regex is present, just add the ^ to take first field content