[英]Python: How can I sum integers in a CSV file, while only summing the integers of a certain variable?
I'm trying to program some data in a csvfile by using Python. 我正在尝试使用Python在csvfile中编程一些数据。 I have a list of countries and results of the Eurovision Songcontest, and it looks like this:
我有一个国家列表和欧洲歌唱大赛的结果,它看起来像这样:
Country,Points,Year
Belgium;181;2016
Netherlands;153;2016
Australia;511;2016
Belgium;217;2015
Australia;196;2015
Et cetera. 等等。
In summary, I want to sum the total of points that any country received throughout the years, so the output should look something like this: 'Belgium: 398','Netherlands: 153','Australia: 707' and so on. 总而言之,我想对所有国家多年来获得的总积分进行汇总,因此输出应如下所示:“比利时:398”,“荷兰:153”,“澳大利亚:707”,依此类推。
This is what my code looks like: 这是我的代码如下所示:
import csv
with open('euro20042016.csv', 'r') as csvfile:
pointsallyears = []
countriesallyears = []
readFILE = csv.reader(csvfile, delimiter=';')
for row in readFILE:
countriesallyears.append(row[0])
pointsallyears.append(row[1])
csvfile.close()
results = []
for result in pointsallyears:
result = int(result)
results.append(result)
scorebord = zip(countriesallyears,results)
So I already made sure that the results / points are actual integers and I filtered out the third row (Year), but I have no idea how to proceed from here. 所以我已经确保结果/点是实际的整数,并且我过滤掉了第三行(年份),但是我不知道如何从这里继续。 Thanks a lot in advance!
在此先多谢!
Just put @Mikk's comment into an actual answer. 只需将@Mikk的评论放入实际答案中即可。 Two lines except the
import
除
import
外的两行
import pandas as pd
df = pd.read_csv('euro20042016.csv', sep = ';')
print df.groupby('Country')['Points'].sum()
The only extra thing you need to do is to change the first line of your file to be delimited by ;
您唯一需要做的额外事情就是更改文件的第一行,以第一行分隔
;
instead of ,
. 而不是
,
。
I slightly changed your code to use a dictionary and used country names as keys. 我稍微更改了您的代码以使用字典,并使用国家/地区名称作为键。 In result dictionary d will have country names as key and value is the total points.
结果字典d将以国家/地区名称作为关键字,值是总分。
import csv
d = dict()
with open('euro20042016.csv', 'r') as csvfile:
readFILE = csv.reader(csvfile, delimiter=';')
print (readFILE)
c_list = []
for row in readFILE:
if row[0] in c_list:
d[row[0]] = d[row[0]] + int(row[1])
else:
c_list.append(row[0])
d[row[0]] = int(row[1])
csvfile.close()
print(d)
I decided to play around a bit with your code, and this is what I came up with. 我决定花点时间处理您的代码,这就是我想到的。 Here,
row[0]
contains the country names, and row[1]
contains the values we need. 在这里,
row[0]
包含国家/地区名称, row[1]
包含我们所需的值。 We check if the country already exists in the dictionary we use to maintain the aggregates, and if it doesn't we create it. 我们检查用于维护聚合的词典中是否已经存在该国家,如果不存在,我们将创建该国家。
import csv
with open('euro20042016.csv', 'r') as csvfile:
score_dict={}
readFILE = csv.reader(csvfile, delimiter=';')
for row in readFILE:
# Only rows with 3 elements have the data we need
if len(row) == 3:
if row[0] in score_dict:
score_dict[row[0]]+=int(row[1])
else:
score_dict[row[0]]=int(row[1])
csvfile.close()
print score_dict
What I get as output is this 我得到的输出是这个
{'Belgium': 398, 'Australia': 707, 'Netherlands': 153}
which I believe is what you were aiming for. 我相信这是您的目标。
Let me know in the comments if you face a problem understanding anything. 如果您在理解任何内容时遇到问题,请在评论中让我知道。
I have solution of that. 我有解决方案。 but make sure your euro20042016.csv file same as
但请确保您的euro20042016.csv文件与
Belgium;181;2016
Netherlands;153;2016
Australia;511;2016
Belgium;217;2015
Australia;196;2015
and this code get output in list. 然后此代码将输出到列表中。 like
喜欢
[('Belgium', 398), ('Australia', 707), ('Netherlands', 153)]
Code is here 代码在这里
try:
f = open('euro20042016.csv', 'r+')
s = f.read()
lst = list(map(lambda x: x.split(';'), s.split('\n')))
points, country = [], []
for line in lst:
points.append(int(line[1]))
country.append(line[0])
countrypoints = sorted(zip(country, points), key=lambda x: x[1])
country = list(set(country))
total = [0]*len(country)
for rec in countrypoints:
total[country.index(rec[0])] = total[country.index(
rec[0])] + rec[1]
f.close()
finalTotal = list(zip(country, total))
print finalTotal
except IOError as ex:
print ex
except Exception as ex:
print ex
I hope this will help you. 我希望这能帮到您。
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