正则表达式停止捕获组在？ 符号

Question

I am trying to capture "thing1" and "thing2" in these strings:

http://www.example.com/stuff1/thing1   
http://www.example.com/stuff2/thing2?id=9999

In python, I tried this:

re.findall('^.*(?:stuff1/|stuff2/)(.*)\??.*$', url)

The first example URL works with my code, but the second gives:

['thing2?id=9999']

I was intending for the capture group to not include the "?" .

Answer 1

Try this:

import re
re.findall('^.*(?:stuff\d\/)(.*?)(?=\?|$).*$', url)

In this regex, I used Positive Lookahead (?= ) to exclude ?

Answer 2

只需捕获“非? ”字符：

re.findall('^.*(?:stuff1/|stuff2/)([^?]*).*$', url)